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Previous years papers CBSE Class XII Mathematics with answers – Year 2003

April 14, 2020

SOLUTION MATHEMATICS CLASS XII NCERT APPLICATION OF DERIVATIVES MISCELLANEOUS EXCERCISE 

April 24, 2020

Show that $2{\tan ^{ – 1}}( – 3) = \frac{{ – \pi }}{2} + {\tan ^{ – 1}}\left( {\frac{{ – 4}}{3}} \right)$.

May 22, 2021