How to integrate $\int_0^{\pi /2} {\frac{{dx}}{{{{\left( {{a^2}{{\cos }^2}x + {b^2}{{\sin }^2}x} \right)}^2}}}} $ ~~~~~[NCERT Exemp. Q. 44,Page 166 ]
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and $I = \int_0^\pi {\frac{{\pi – x}}{{1 + \sin (\pi – x)}}} dx = \int_0^\pi {\frac{{\pi – x}}{{1 + \sin…