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April 18, 2021/

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April 18, 2021/

Let $I = \int {\frac{{2x – 1}}{{2x + 3}}} dx = \int {\frac{{2x + 3 – 3 – 1}}{{2x + 3}}} dx$ $ = \int 1 dx – 4\int {\frac{1}{{2x + 3}}} dx = x – \int {\frac{4}{{2\left( {x + \frac{3}{2}} \right)}}} dx$ $ = x – 2\log + \left| {\left( {x +…

March 16, 2021/

Find the area of the region bounded by ${x^2} = 4y,y = 2,$$y = 4$ and the $y$-axis in the first quadrant [ NCERT Ex. 8.1, Q.3,Page 366]

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