• Rated 0 out of 5
Sale!
Original price was: ₹105.00.Current price is: ₹85.00.
• Rated 0 out of 5
Sale!
Original price was: ₹85.00.Current price is: ₹75.00.
• Rated 0 out of 5
Sale!
Original price was: ₹85.00.Current price is: ₹75.00.
• Rated 0 out of 5
Sale!
Original price was: ₹85.00.Current price is: ₹75.00.
Edit Template

# $therefore, $${\rm{LHS}} = {\tan ^{ – 1}}\left( {\frac{{\sqrt 2 \cos \theta + \sqrt 2 \sin \theta }}{{\sqrt 2 \cos \theta – \sqrt 2 \sin \theta }}} \right) # = {\tan ^{ – 1}}\left( {\frac{{\cos \theta + \sin \theta }}{{\cos \theta – \sin \theta }}} \right) # = {\tan ^{ – 1}}\left( {\frac{{1 + \tan \theta }}{{1 – \tan \theta }}} \right) = {\tan ^{ – 1}}\left( {\frac{{\tan \frac{\pi }{4} + \tan \theta }}{{1 – \tan \frac{\pi }{4} \cdot \tan \theta }}} \right) # = {\tan ^{ – 1}}\left[ {\tan \left( {\frac{\pi }{4} + \theta } \right)} \right] = \frac{\pi }{4} + \theta = \frac{\pi }{4} + \frac{1}{2}{\cos ^{ – 1}}{x^2}$$ = {\rm{RHS}}$ Hence proved.

## Company

Our ebook website brings you the convenience of instant access to a diverse range of titles, spanning genres from fiction and non-fiction to self-help, business.

## Most Recent Posts

• All Post
• Board Curriculum
• Competitive Exams
• Reference Guides
• Uncategorized

## Category

Our ebook website brings you the convenience of instant access.