Evaluate $\cos \left[ {{{\cos }^{ – 1}}\left( {\frac{{ – \sqrt 3 }}{2}} \right) + \frac{\pi }{6}} \right]$.[NCERT,Exemplar.3,Q.2,Page.35] Post author:admin Post published:May 15, 2021 Post category:Uncategorized We have, $\cos \left[ {{{\cos }^{ – 1}}\left( {\frac{{ – \sqrt 3 }}{2}} \right) + \frac{\pi }{6}} \right] = \cos \left[ {{{\cos }^{ – 1}}\left( {\cos \frac{{5\pi }}{6}} \right) + \frac{\pi }{6}} \right]$ $ = \cos \left( {\frac{{5\pi }}{6} + \frac{\pi }{6}} \right)$ $ = \cos \left( {\frac{{6\pi }}{6}} \right)$$ = \cos (\pi ) = – 1$ PURCHASE MATHEMATICS E – BOOKS : www.mathstudy.in Please Share This Share this content Opens in a new window Opens in a new window Opens in a new window Opens in a new window Opens in a new window Opens in a new window Opens in a new window Opens in a new window Opens in a new window Opens in a new window Opens in a new window You Might Also Like 1st grade subtraction word problems June 1, 2021 mathematics level 2 question papers July 1, 2021 sat mathematics level 2 July 1, 2021