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Let $I = \int {\frac{{2x – 1}}{{2x + 3}}} dx = \int {\frac{{2x + 3 – 3 – 1}}{{2x + 3}}} dx$ $ = \int 1 dx – 4\int {\frac{1}{{2x + 3}}} dx = x – \int {\frac{4}{{2\left( {x + \frac{3}{2}} \right)}}} dx$ $ = x – 2\log + \left| {\left( {x +…
![Find the area of the region in the first quadrant enclosed by x-axis, line x = sqrt 3 y and the circle x^2 + y^2 = 4[ NCERT Ex. 8.1, Q.6,Page 366]](https://mathstudy.in/wp-content/uploads/Find-the-area-of-the-region-in-the-first-quadrant-enclosed-by-x-axis-line-x-sqrt-3-y-and-the-circle-x2-y2-4-NCERT-Ex.-8.1-Q.6Page-366.jpg)
Find the area of the region in the first quadrant enclosed by x-axis, line x = \sqrt 3 y and the circle x^2 + y^2 = 4[ NCERT Ex. 8.1, Q.6,Page 366]
![Find the area of the region bounded by the ellipse 9x^2+4y^2=36. [ NCERT Ex. 8.1, Q.5,Page 366]](https://mathstudy.in/wp-content/uploads/Find-the-area-of-the-region-bounded-by-the-ellipse-9x24y236.-NCERT-Ex.-8.1-Q.5Page-366.jpg)
Find the area of the region bounded by the ellipse x^2/4 + y^2/9 = 1, 9x^2+4y^2=36. [ NCERT Ex. 8.1, Q.5,Page 366]
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